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SHA1 Hash:c009363094fcb7a2b91a11159dd184cfb9f86809
Date: 2013-04-06 14:43:56
User: kinaba
Comment:TCOR2A
Timelines: family | ancestors | descendants | both | trunk
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Added SRM/TCO13-2A-U/1A.cpp version [8773ddd5052442db]

1 +#include <iostream> 2 +#include <sstream> 3 +#include <iomanip> 4 +#include <vector> 5 +#include <string> 6 +#include <map> 7 +#include <set> 8 +#include <algorithm> 9 +#include <numeric> 10 +#include <iterator> 11 +#include <functional> 12 +#include <complex> 13 +#include <queue> 14 +#include <stack> 15 +#include <cmath> 16 +#include <cassert> 17 +using namespace std; 18 +typedef long long LL; 19 +typedef long double LD; 20 +typedef complex<LD> CMP; 21 + 22 +template<typename T> 23 +struct DP2 24 +{ 25 + const int N1, N2; 26 + vector<T> data; 27 + DP2(int N1, int N2, const T& t = T()) 28 + : N1(N1), N2(N2), data(N1*N2, t) { assert(data.size()*sizeof(T)<(1<<26)); } 29 + T& operator()(int i1, int i2) 30 + { return data[ (i1*N2)+i2 ]; } 31 + void swap(DP2& rhs) 32 + { data.swap(rhs.data); } 33 +}; 34 + 35 +class TheLargestString { public: 36 + string find(string s, string t) 37 + { 38 + const int N = s.size(); 39 + DP2< pair<string,string> > best(N+1,N+1); 40 + for(int i=N-1; i>=0; --i) 41 + { 42 + for(int len=1; len<=N-i; ++len) 43 + { 44 + pair<string, string> cand = best(i+1, len); 45 + pair<string, string> cand2(s[i]+best(i+1, len-1).first, t[i]+best(i+1,len-1).second); 46 + if(cand.first+cand.second < cand2.first+cand2.second) 47 + cand = cand2; 48 + best(i, len) = cand; 49 + } 50 + } 51 + string ans; 52 + for(int len=0; len<=N; ++len) 53 + ans = max(ans, best(0,len).first + best(0,len).second); 54 + return ans; 55 + } 56 +}; 57 + 58 +// BEGIN CUT HERE 59 +#include <ctime> 60 +double start_time; string timer() 61 + { ostringstream os; os << " (" << int((clock()-start_time)/CLOCKS_PER_SEC*1000) << " msec)"; return os.str(); } 62 +template<typename T> ostream& operator<<(ostream& os, const vector<T>& v) 63 + { os << "{ "; 64 + for(typename vector<T>::const_iterator it=v.begin(); it!=v.end(); ++it) 65 + os << '\"' << *it << '\"' << (it+1==v.end() ? "" : ", "); os << " }"; return os; } 66 +void verify_case(const string& Expected, const string& Received) { 67 + bool ok = (Expected == Received); 68 + if(ok) cerr << "PASSED" << timer() << endl; else { cerr << "FAILED" << timer() << endl; 69 + cerr << "\to: \"" << Expected << '\"' << endl << "\tx: \"" << Received << '\"' << endl; } } 70 +#define CASE(N) {cerr << "Test Case #" << N << "..." << flush; start_time=clock(); 71 +#define END verify_case(_, TheLargestString().find(s, t));} 72 +int main(){ 73 +CASE(0) 74 + string s = "ab"; 75 + string t = "zy"; 76 + string _ = "by"; 77 +END 78 +CASE(1) 79 + string s = "abacaba"; 80 + string t = "zzzaaaa"; 81 + string _ = "cbaaaa"; 82 +END 83 +CASE(2) 84 + string s = "x"; 85 + string t = "x"; 86 + string _ = "xx"; 87 +END 88 +CASE(3) 89 + string s = "abbabbabbababaaaabbababab"; 90 + string t = "bababbaabbbababbbbababaab"; 91 + string _ = "bbbbbbbbbbbbbbbbbbaaab"; 92 +END 93 +/* 94 +CASE(4) 95 + string s = ; 96 + string t = ; 97 + string _ = ; 98 +END 99 +CASE(5) 100 + string s = ; 101 + string t = ; 102 + string _ = ; 103 +END 104 +*/ 105 +} 106 +// END CUT HERE

Added SRM/TCO13-2A-U/1C-U.cpp version [5a2518f603d02674]

1 +#include <iostream> 2 +#include <sstream> 3 +#include <iomanip> 4 +#include <vector> 5 +#include <string> 6 +#include <map> 7 +#include <set> 8 +#include <algorithm> 9 +#include <numeric> 10 +#include <iterator> 11 +#include <functional> 12 +#include <complex> 13 +#include <queue> 14 +#include <stack> 15 +#include <cmath> 16 +#include <cassert> 17 +using namespace std; 18 +typedef long long LL; 19 +typedef long double LD; 20 +typedef complex<LD> CMP; 21 + 22 +class ThePowers { public: 23 + long long find(int A, int B) 24 + { 25 + LL total = 1; 26 + 27 + int prev_cnt = 1; 28 + for(int K=31; K>=1; --K) 29 + { 30 + int ub = invpow(A,K); 31 + int cnt = num_ppprime_under(ub); 32 + LL x = solve2(K,B) * (cnt - prev_cnt); 33 + total += x; 34 + prev_cnt = cnt; 35 + } 36 + return total; 37 + } 38 + 39 + // max x s.t. x^K <= A; 40 + int invpow(int A, int K) 41 + { 42 + int v = 0; 43 + int c = (int)pow(A, 1.0/K); 44 + for(int x=max(1,c-3); x<=c+3; ++x) 45 + if( pow_leq(x, K, A) ) 46 + v = x; 47 + return v; 48 + } 49 + 50 + // number of non-square, cubic, ... numbers in [1,N] 51 + int num_ppprime_under(int N) 52 + { 53 + int total = N; 54 + vector<int> num(32); 55 + for(int p=num.size()-1; p>=2; --p) 56 + { 57 + num[p] = invpow(N, p) - 1; 58 + for(int q=p+p; q<num.size(); q+=p) 59 + num[p] -= num[q]; 60 + total -= num[p]; 61 + } 62 + return total; 63 + } 64 + 65 + int pow_leq(int x, int p, int N) 66 + { 67 + LL v = 1; 68 + for(int i=0; i<p; ++i) { 69 + v *= x; 70 + if(v>N) 71 + return false; 72 + } 73 + return true; 74 + } 75 + 76 + // number of [1,K]*[1,B] 77 + LL solve2(int K, int B) 78 + { 79 + set<LL> test; 80 + for(LL x=1; x<=K; ++x) 81 + for(LL y=1; y<=B; ++y) 82 + test.insert(x*y); 83 + return test.size(); 84 + } 85 +}; 86 + 87 +// BEGIN CUT HERE 88 +#include <ctime> 89 +double start_time; string timer() 90 + { ostringstream os; os << " (" << int((clock()-start_time)/CLOCKS_PER_SEC*1000) << " msec)"; return os.str(); } 91 +template<typename T> ostream& operator<<(ostream& os, const vector<T>& v) 92 + { os << "{ "; 93 + for(typename vector<T>::const_iterator it=v.begin(); it!=v.end(); ++it) 94 + os << '\"' << *it << '\"' << (it+1==v.end() ? "" : ", "); os << " }"; return os; } 95 +void verify_case(const long long& Expected, const long long& Received) { 96 + bool ok = (Expected == Received); 97 + if(ok) cerr << "PASSED" << timer() << endl; else { cerr << "FAILED" << timer() << endl; 98 + cerr << "\to: \"" << Expected << '\"' << endl << "\tx: \"" << Received << '\"' << endl; } } 99 +#define CASE(N) {cerr << "Test Case #" << N << "..." << flush; start_time=clock(); 100 +#define END verify_case(_, ThePowers().find(A, B));} 101 +int main(){ 102 + 103 +CASE(0) 104 + int A = 7; 105 + int B = 4; 106 + long long _ = 23LL; 107 +END 108 +CASE(1) 109 + int A = 1; 110 + int B = 1; 111 + long long _ = 1LL; 112 +END 113 +CASE(2) 114 + int A = 1000000000; 115 + int B = 1000000000; 116 + long long _ = 999983644283653287LL; 117 +END 118 +CASE(3) 119 + int A = 999999999; 120 + int B = 5; 121 + long long _ = 4999934406LL; 122 +END 123 +/* 124 +CASE(4) 125 + int A = ; 126 + int B = ; 127 + long long _ = LL; 128 +END 129 +CASE(5) 130 + int A = ; 131 + int B = ; 132 + long long _ = LL; 133 +END 134 +*/ 135 +} 136 +// END CUT HERE